3(x^2)-90x+350=0

Solution for 3(x^2)-90x+350=0 equation:

3(x^2)-90x+350=0

a = 3; b = -90; c = +350;
Δ = b2-4ac
Δ = -902-4·3·350
Δ = 3900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3900}=\sqrt{100*39}=\sqrt{100}*\sqrt{39}=10\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-10\sqrt{39}}{2*3}=\frac{90-10\sqrt{39}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+10\sqrt{39}}{2*3}=\frac{90+10\sqrt{39}}{6}
$